FORUMS - COASTERFORCE
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Parc Asterix |"Oz'Iris"| B&M Invert
- Thread starter Rush
- Start date
Ethan
Strata Poster
Re: "Unknown", B&M Invert for Parc Asterix
I've ridden Nemesis, Inferno, Black Mamba, Dragon Challenge and Raptor (CP). I've been on loads of zero g rolls but I have never felt weightless either way. Lateral or vertical. I don't concentrate on forces when i'm actually riding a coaster unless it's a hyper or something like that. Just because i'm not a genius at physics doesn't mean I haven't done something that simple -_-
I've ridden Nemesis, Inferno, Black Mamba, Dragon Challenge and Raptor (CP). I've been on loads of zero g rolls but I have never felt weightless either way. Lateral or vertical. I don't concentrate on forces when i'm actually riding a coaster unless it's a hyper or something like that. Just because i'm not a genius at physics doesn't mean I haven't done something that simple -_-
A
Anonymous
Guest
Re: "Unknown", B&M Invert for Parc Asterix
^^ You still experience a lateral force, I did however said that it had "lateral movement", meaning that the entrance and exit are not lined up not a straight zero-g as most others are...
^^ You still experience a lateral force, I did however said that it had "lateral movement", meaning that the entrance and exit are not lined up not a straight zero-g as most others are...
SaiyanHajime
CF Legend
Re: "Unknown", B&M Invert for Parc Asterix
It's like Loefet said, it's just moving slightly to one side so it's not a "perfect" heartline. Every inversion has to be slightly different to fit the requirements so It's still just a zero g.
I'm so excited for this ride, and being Parc Asterix we can expect some fabulous theming too. So excited.
It's like Loefet said, it's just moving slightly to one side so it's not a "perfect" heartline. Every inversion has to be slightly different to fit the requirements so It's still just a zero g.
I'm so excited for this ride, and being Parc Asterix we can expect some fabulous theming too. So excited.
Nemesis Inferno
Strata Poster
Re: "Unknown", B&M Invert for Parc Asterix
I think the assumption is Egyptian, since they're the only major characters from the series who haven't got a ride or area at the moment...
nadroJ said:
I think the assumption is Egyptian, since they're the only major characters from the series who haven't got a ride or area at the moment...
jordypordy11
Mega Poster
Re: "Unknown", B&M Invert for Parc Asterix
its almost finished!
another update! :lol:
i so cant wait for this to start testing, and for a pov :--D :--D
http://www.potionmagix.fr/forumix/post44606.html#p44606
its almost finished!
another update! :lol:
i so cant wait for this to start testing, and for a pov :--D :--D
http://www.potionmagix.fr/forumix/post44606.html#p44606
iblamefish
Roller Poster
Re: "Unknown", B&M Invert for Parc Asterix
Good call - the new pics confirm what you said
Let's hope it's a gentle-to-non-existent affair!
Good call - the new pics confirm what you said
Let's hope it's a gentle-to-non-existent affair!
Hixee said:
iblamefish
Roller Poster
Re: "Unknown", B&M Invert for Parc Asterix
Absolutely correct. Which is why this is *not* a zero G roll. To achieve zero-g, the rider must travel in a parabolic curve. On an inverted coaster, this means that the top of the track must be flat - Katun is a perfect example:
The top of this element is curved - which means that the riders will not travel in a parabola, meaning that they're not falling at the rate of gravity, meaning that they're not weightless.
Sorry to be such a pedant, but I didn't study mechanical engineering with the hope of being a rollercoaster designer for nothing (now a web developer, heh :/ ).
Hixee said:
Absolutely correct. Which is why this is *not* a zero G roll. To achieve zero-g, the rider must travel in a parabolic curve. On an inverted coaster, this means that the top of the track must be flat - Katun is a perfect example:
The top of this element is curved - which means that the riders will not travel in a parabola, meaning that they're not falling at the rate of gravity, meaning that they're not weightless.
Sorry to be such a pedant, but I didn't study mechanical engineering with the hope of being a rollercoaster designer for nothing (now a web developer, heh :/ ).
Xpress
Strata Poster
Re: "Unknown", B&M Invert for Parc Asterix
The top of the element does not have to be flat in order to achieve a zero gravity situation.
The element in the top left is not hardly flat at all ontop, and yet it is a zero-g-roll.
This element is also a zero gravity element.
First and second inversions on Tatsu. And i'm pretty certain the last roll on Tatsu is also a zero-gravity element...
iblamefish said:
The top of the element does not have to be flat in order to achieve a zero gravity situation.
The element in the top left is not hardly flat at all ontop, and yet it is a zero-g-roll.
This element is also a zero gravity element.
First and second inversions on Tatsu. And i'm pretty certain the last roll on Tatsu is also a zero-gravity element...
Antinos
Slut for Spinners
Re: "Unknown", B&M Invert for Parc Asterix
Or we can take an inverted coaster to show the example as well, like Phaethon:
It's not flat on top. It's all about how the entire element is shaped that determines 0-g. In Katun's case, the 0-g roll is very tall and the train travels at a slower speed, which requires a smaller parabola. Phaethon's is shorter and the track also rolls slower than Katun's, requiring a larger parabola. In this case, there will be 0-g. The transitions into and out of the element are banked, so the only lateral forces you will experience will be due to the train's rotation.
Or we can take an inverted coaster to show the example as well, like Phaethon:
It's not flat on top. It's all about how the entire element is shaped that determines 0-g. In Katun's case, the 0-g roll is very tall and the train travels at a slower speed, which requires a smaller parabola. Phaethon's is shorter and the track also rolls slower than Katun's, requiring a larger parabola. In this case, there will be 0-g. The transitions into and out of the element are banked, so the only lateral forces you will experience will be due to the train's rotation.